Quadratic Rule from a Table of Values

How do you find a quadratic rule from a table of values?

For example,

x1 2 3 4
y061424

Find the first difference

First Difference6-0=614-6=824-14=10

Find the second difference (if the second difference is a constant, then it is quadratic)

Second Difference8-6=2 10-8=2

The general equation of a quadratic is y=ax^2+bx+c

The second difference is 2a

Hence our equation is now y=x^2+bx+c

The c value is the vertical intercept (x=0). We can back track in the table

x01234
yc061424

As the first differences are 6, 8, 10, the one between 0 and 1 must be 4

0-c=4

c=-4

Our equation is now y=x^2+bx-4.

We can now use any other point to find the b value.

Let’s use the point (2, 6)

6=2^2+b(2)-4

6=4-2b-4

6=2b

b=3

The function is y=x^2+3x-4

Let’s try another one

x3456
y7173149

First differences

First difference101418

Second difference

Second Difference44

Hence 2a=4, therefore a=2

The equation is now y=2x^2+bx+c

Instead of back tracking, this time I am going to use two points and simultaneous equations.

Using points (3, 7) and (4, 17)

    \[7=2(3)^2+b(3)+c\]

(1)   \begin{equation*}3b+c=-11\end{equation*}

    \[17=2(4)^2+b(4)+c\]

(2)   \begin{equation*}4b+c=-15\end{equation*}

Equation 2 – Equation 1

b=-4

Substitute b=-4 into equation 1

3(-4)+c=-11

-12+c=-11

c=1

Hence the equation is y=2x^2-4x+1

Leave a Comment

Filed under Quadratics, Uncategorized

Leave a Reply

Your email address will not be published. Required fields are marked *